0(2x-4)=6(x+2)

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Solution for 0(2x-4)=6(x+2) equation: 



0(2x-4)=6(x+2)

We move all terms to the left:

0(2x-4)-(6(x+2))=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

0(2x-4)-6x-12=0

We add all the numbers together, and all the variables

-6x+0(2x-4)-12=0

We move all terms containing x to the left, all other terms to the right

-6x+0(2x-4)=12

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