0,002x2=0,05

Solution for 0,002x2=0,05 equation:

0.002x^2=0.05

We move all terms to the left:

0.002x^2-(0.05)=0

We add all the numbers together, and all the variables

0.002x^2-0.05=0

a = 0.002; b = 0; c = -0.05;
Δ = b2-4ac
Δ = 02-4·0.002·(-0.05)
Δ = 0.0004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.0004}}{2*0.002}=\frac{0-\sqrt{0.0004}}{0.004}
=-\frac{\sqrt{}}{0.004}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.0004}}{2*0.002}=\frac{0+\sqrt{0.0004}}{0.004}
=\frac{\sqrt{}}{0.004}
$