0,12x-(3-0,08x)=-0,3x+6

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Solution for 0,12x-(3-0,08x)=-0,3x+6 equation:



0.12x-(3-0.08x)=-0.3x+6
We move all terms to the left:
0.12x-(3-0.08x)-(-0.3x+6)=0
We add all the numbers together, and all the variables
0.12x-(-0.08x+3)-(-0.3x+6)=0
We get rid of parentheses
0.12x+0.08x+0.3x-3-6=0
We add all the numbers together, and all the variables
0.5x-9=0
We move all terms containing x to the left, all other terms to the right
0.5x=9
x=9/0.5
x=18

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