0,1y-1=0,2y-2-0,3y+3

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Solution for 0,1y-1=0,2y-2-0,3y+3 equation: 



0.1y-1=0.2y-2-0.3y+3

We move all terms to the left:

0.1y-1-(0.2y-2-0.3y+3)=0

We add all the numbers together, and all the variables

0.1y-(-0.1y+1)-1=0

We get rid of parentheses

0.1y+0.1y-1-1=0

We add all the numbers together, and all the variables

0.2y-2=0

We move all terms containing y to the left, all other terms to the right

0.2y=2

y=2/0.2

y=10

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