0,2(10x+3)+3x=4(2x-2)+3,8

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Solution for 0,2(10x+3)+3x=4(2x-2)+3,8 equation:



0.2(10x+3)+3x=4(2x-2)+3.8
We move all terms to the left:
0.2(10x+3)+3x-(4(2x-2)+3.8)=0
We add all the numbers together, and all the variables
3x+0.2(10x+3)-(4(2x-2)+3.8)=0
We multiply parentheses
3x+2x-(4(2x-2)+3.8)+0.6=0
We calculate terms in parentheses: -(4(2x-2)+3.8), so:
4(2x-2)+3.8
We multiply parentheses
8x-8+3.8
We add all the numbers together, and all the variables
8x-4.2
Back to the equation:
-(8x-4.2)
We add all the numbers together, and all the variables
5x-(8x-4.2)+0.6=0
We get rid of parentheses
5x-8x+4.2+0.6=0
We add all the numbers together, and all the variables
-3x+4.8=0
We move all terms containing x to the left, all other terms to the right
-3x=-4.8
x=-4.8/-3
x=1+1/1.6666666666667

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