0,2*(z-6)=1/6*(5-z)

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Solution for 0,2*(z-6)=1/6*(5-z) equation: 



0.2(z-6)=1/6(5-z)

We move all terms to the left:

0.2(z-6)-(1/6(5-z))=0



Domain of the equation: 6(5-z))!=0

z∈R



We add all the numbers together, and all the variables

0.2(z-6)-(1/6(-1z+5))=0

We multiply parentheses

0.2z-(1/6(-1z+5))-1.2=0

We multiply all the terms by the denominator


(0.2z)*6(-1z+5))-(1-(1.2)*6(-1z+5))=0

We add all the numbers together, and all the variables

(+0.2z)*6(-1z+5))-(1-(1.2)*6(-1z+5))=0

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