0,25=ln(2/x)

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Solution for 0,25=ln(2/x) equation: 


D( x )

x = 0

2/x <= 0

x = 0

x = 0

2/x <= 0

2/x <= 0

2*x^-1 <= 0

2*x^-1 <= 0 // : 2

x^-1 <= 0/2

x^-1 <= 0

1/(x^1) <= 0

x <> 0

1/(x^1) <= 0 // * x^2

(x^2)/(x^1) <= 0

x^1 <= 0

x <= 0

x in (-oo:0)

x in (0:+oo)

0.25 = ln(2/x) // - ln(2/x)

0.25-ln(2/x) = 0

0.25-ln(2/x) = 0 // - 0.25

-ln(2/x) = -0.25

-ln(2/x) = -0.25 // * -1

ln(2/x) = ln(e^0.25)

2/x = e^0.25

2/x-e^0.25 = 0

2*x^-1 = e^0.25 // : 2

x^-1 = (e^0.25)/2

-1 < 0

1/(x^1) = (e^0.25)/2 // * x^1

1 = ((e^0.25)/2)*x^1 // : (e^0.25)/2

2*e^-0.25 = x^1

x = 2*e^-0.25

x = 2*e^-0.25

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