0,4(y-5)=0,3(y+1)+1,2

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Solution for 0,4(y-5)=0,3(y+1)+1,2 equation:



0.4(y-5)=0.3(y+1)+1.2
We move all terms to the left:
0.4(y-5)-(0.3(y+1)+1.2)=0
We multiply parentheses
0.4y-(0.3(y+1)+1.2)-2=0
We calculate terms in parentheses: -(0.3(y+1)+1.2), so:
0.3(y+1)+1.2
We multiply parentheses
0.3y+0.3+1.2
We add all the numbers together, and all the variables
0.3y+1.5
Back to the equation:
-(0.3y+1.5)
We get rid of parentheses
0.4y-0.3y-1.5-2=0
We add all the numbers together, and all the variables
0.1y-3.5=0
We move all terms containing y to the left, all other terms to the right
0.1y=3.5
y=3.5/0.1
y=35

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