0,4(y-5)=0,3(y+1)+1,2

Solution for 0,4(y-5)=0,3(y+1)+1,2 equation:

0.4(y-5)=0.3(y+1)+1.2

We move all terms to the left:

0.4(y-5)-(0.3(y+1)+1.2)=0

We multiply parentheses

0.4y-(0.3(y+1)+1.2)-2=0


We calculate terms in parentheses: -(0.3(y+1)+1.2), so:

0.3(y+1)+1.2

We multiply parentheses

0.3y+0.3+1.2

We add all the numbers together, and all the variables

0.3y+1.5

Back to the equation:

-(0.3y+1.5)


We get rid of parentheses

0.4y-0.3y-1.5-2=0

We add all the numbers together, and all the variables

0.1y-3.5=0

We move all terms containing y to the left, all other terms to the right

0.1y=3.5

y=3.5/0.1

y=35