0,5(4x+6)+2(3x-2)=3(3x-1)+8(x-2)

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Solution for 0,5(4x+6)+2(3x-2)=3(3x-1)+8(x-2) equation:



0.5(4x+6)+2(3x-2)=3(3x-1)+8(x-2)
We move all terms to the left:
0.5(4x+6)+2(3x-2)-(3(3x-1)+8(x-2))=0
We multiply parentheses
2x+6x-(3(3x-1)+8(x-2))+3-4=0
We calculate terms in parentheses: -(3(3x-1)+8(x-2)), so:
3(3x-1)+8(x-2)
We multiply parentheses
9x+8x-3-16
We add all the numbers together, and all the variables
17x-19
Back to the equation:
-(17x-19)
We add all the numbers together, and all the variables
8x-(17x-19)-1=0
We get rid of parentheses
8x-17x+19-1=0
We add all the numbers together, and all the variables
-9x+18=0
We move all terms containing x to the left, all other terms to the right
-9x=-18
x=-18/-9
x=+2

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