0,5(4z+1)=(4,5-2,5z)-2(2-0,5z)

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Solution for 0,5(4z+1)=(4,5-2,5z)-2(2-0,5z) equation: 



0.5(4z+1)=(4.5-2.5z)-2(2-0.5z)

We move all terms to the left:

0.5(4z+1)-((4.5-2.5z)-2(2-0.5z))=0

We add all the numbers together, and all the variables

0.5(4z+1)-((-2.5z+4.5)-2(-0.5z+2))=0

We multiply parentheses

2z-((-2.5z+4.5)-2(-0.5z+2))+0.5=0



We calculate terms in parentheses: -((-2.5z+4.5)-2(-0.5z+2)), so:

(-2.5z+4.5)-2(-0.5z+2)

We multiply parentheses

(-2.5z+4.5)-0z-4

We get rid of parentheses

-2.5z-0z+4.5-4

We add all the numbers together, and all the variables

-3.5z+0.5

Back to the equation:

-(-3.5z+0.5)



We get rid of parentheses

2z+3.5z-0.5+0.5=0

We add all the numbers together, and all the variables

5.5z=0

z=0/5.5

z=0

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