0,5(4z+1)=(4,5-2,5z)-2(2-05z)

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Solution for 0,5(4z+1)=(4,5-2,5z)-2(2-05z) equation:



0.5(4z+1)=(4.5-2.5z)-2(2-05z)
We move all terms to the left:
0.5(4z+1)-((4.5-2.5z)-2(2-05z))=0
We add all the numbers together, and all the variables
0.5(4z+1)-((-2.5z+4.5)-2(-5z+2))=0
We multiply parentheses
2z-((-2.5z+4.5)-2(-5z+2))+0.5=0
We calculate terms in parentheses: -((-2.5z+4.5)-2(-5z+2)), so:
(-2.5z+4.5)-2(-5z+2)
We multiply parentheses
(-2.5z+4.5)+10z-4
We get rid of parentheses
-2.5z+10z+4.5-4
We add all the numbers together, and all the variables
7.5z+0.5
Back to the equation:
-(7.5z+0.5)
We get rid of parentheses
2z-7.5z-0.5+0.5=0
We add all the numbers together, and all the variables
-5.5z=0
z=0/-5.5
z=0

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