0,5(x-2)=1-(0,2x+1)

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Solution for 0,5(x-2)=1-(0,2x+1) equation: 



0.5(x-2)=1-(0.2x+1)

We move all terms to the left:

0.5(x-2)-(1-(0.2x+1))=0

We multiply parentheses

0.5x-(1-(0.2x+1))-1=0



We calculate terms in parentheses: -(1-(0.2x+1)), so:

1-(0.2x+1)

determiningTheFunctionDomain
-(0.2x+1)+1

We get rid of parentheses

-0.2x-1+1

We add all the numbers together, and all the variables

-0.2x

Back to the equation:

-(-0.2x)



We get rid of parentheses

0.5x+0.2x-1=0

We add all the numbers together, and all the variables

0.7x-1=0

We move all terms containing x to the left, all other terms to the right

0.7x=1

x=1/0.7

x=1+0.3/0.7

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