0,5(x-4)-7,3=0,8(2-x)

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Solution for 0,5(x-4)-7,3=0,8(2-x) equation: 



0.5(x-4)-7.3=0.8(2-x)

We move all terms to the left:

0.5(x-4)-7.3-(0.8(2-x))=0

We add all the numbers together, and all the variables

0.5(x-4)-(0.8(-1x+2))-7.3=0

We multiply parentheses

0.5x-(0.8(-1x+2))-2-7.3=0



We calculate terms in parentheses: -(0.8(-1x+2)), so:

0.8(-1x+2)

We multiply parentheses

-0.8x+1.6

Back to the equation:

-(-0.8x+1.6)



We add all the numbers together, and all the variables

0.5x-(-0.8x+1.6)-9.3=0

We get rid of parentheses

0.5x+0.8x-1.6-9.3=0

We add all the numbers together, and all the variables

1.3x-10.9=0

We move all terms containing x to the left, all other terms to the right

1.3x=10.9

x=10.9/1.3

x=8+0.5/1.3

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