0,5x-(6+0,2x)=(4x-3)/5-1,4

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Solution for 0,5x-(6+0,2x)=(4x-3)/5-1,4 equation: 



0.5x-(6+0.2x)=(4x-3)/5-1.4

We move all terms to the left:

0.5x-(6+0.2x)-((4x-3)/5-1.4)=0

We add all the numbers together, and all the variables

0.5x-(0.2x+6)-((4x-3)/5-1.4)=0

We get rid of parentheses

0.5x-0.2x-((4x-3)/5-1.4)-6=0

We multiply all the terms by the denominator


(0.5x)*5-1.4)-(0.2x)*5-1.4)-((4x-3)-6*5-1.4)=0

We add all the numbers together, and all the variables

(+0.5x)*5+0.2x)*5-1.4)-((4x-1.4)-(-3)-6*5-1.4)=0

We add all the numbers together, and all the variables

(+0.5x)*5+0.2x)*5-1.4)-((4x=0

We multiply parentheses

0x+0.2x)*5-1.4)-((4x=0

We add all the numbers together, and all the variables

x+0.2x)*5-1.4)-((4x=0

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