0,6(40-y)-0.2y=10

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Solution for 0,6(40-y)-0.2y=10 equation: 



0.6(40-y)-0.2y=10

We move all terms to the left:

0.6(40-y)-0.2y-(10)=0

We add all the numbers together, and all the variables

0.6(-1y+40)-0.2y-10=0

We add all the numbers together, and all the variables

-0.2y+0.6(-1y+40)-10=0

We multiply parentheses

-0.2y-0.6y+24-10=0

We add all the numbers together, and all the variables

-0.8y+14=0

We move all terms containing y to the left, all other terms to the right

-0.8y=-14

y=-14/-0.8

y=17+0.4/0.8

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