0,6(x+2)-(0,4x-0,6)=0,2(1-x)

Solution for 0,6(x+2)-(0,4x-0,6)=0,2(1-x) equation:

0.6(x+2)-(0.4x-0.6)=0.2(1-x)

We move all terms to the left:

0.6(x+2)-(0.4x-0.6)-(0.2(1-x))=0

We add all the numbers together, and all the variables

0.6(x+2)-(0.4x-0.6)-(0.2(-1x+1))=0

We multiply parentheses

0.6x-(0.4x-0.6)-(0.2(-1x+1))+1.2=0

We get rid of parentheses

0.6x-0.4x-(0.2(-1x+1))+0.6+1.2=0


We calculate terms in parentheses: -(0.2(-1x+1)), so:

0.2(-1x+1)

We multiply parentheses

-0.2x+0.2

Back to the equation:

-(-0.2x+0.2)


We add all the numbers together, and all the variables

0.2x-(-0.2x+0.2)+1.8=0

We get rid of parentheses

0.2x+0.2x-0.2+1.8=0

We add all the numbers together, and all the variables

0.4x+1.6=0

We move all terms containing x to the left, all other terms to the right

0.4x=-1.6

x=-1.6/0.4

x=-4