0,6*(3+t)=0,2*(1-t)

Solution for 0,6*(3+t)=0,2*(1-t) equation:

0.6(3+t)=0.2(1-t)

We move all terms to the left:

0.6(3+t)-(0.2(1-t))=0

We add all the numbers together, and all the variables

0.6(t+3)-(0.2(-1t+1))=0

We multiply parentheses

0.6t-(0.2(-1t+1))+1.8=0


We calculate terms in parentheses: -(0.2(-1t+1)), so:

0.2(-1t+1)

We multiply parentheses

-0.2t+0.2

Back to the equation:

-(-0.2t+0.2)


We get rid of parentheses

0.6t+0.2t-0.2+1.8=0

We add all the numbers together, and all the variables

0.8t+1.6=0

We move all terms containing t to the left, all other terms to the right

0.8t=-1.6

t=-1.6/0.8

t=-2