0,8(2u-3)=(2u+4)*0,6

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Solution for 0,8(2u-3)=(2u+4)*0,6 equation: 



0.8(2u-3)=(2u+4)*0.6

We move all terms to the left:

0.8(2u-3)-((2u+4)*0.6)=0

We multiply parentheses

1.6u-((2u+4)*0.6)-2.4=0



We calculate terms in parentheses: -((2u+4)*0.6), so:

(2u+4)*0.6

We multiply parentheses

1.2u+2.4

Back to the equation:

-(1.2u+2.4)



We get rid of parentheses

1.6u-1.2u-2.4-2.4=0

We add all the numbers together, and all the variables

0.4u-4.8=0

We move all terms containing u to the left, all other terms to the right

0.4u=4.8

u=4.8/0.4

u=11+0.4/0.4

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