0,8(3x-2)-10,1=0,3(x-4)

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Solution for 0,8(3x-2)-10,1=0,3(x-4) equation: 



0.8(3x-2)-10.1=0.3(x-4)

We move all terms to the left:

0.8(3x-2)-10.1-(0.3(x-4))=0

We multiply parentheses

2.4x-(0.3(x-4))-1.6-10.1=0



We calculate terms in parentheses: -(0.3(x-4)), so:

0.3(x-4)

We multiply parentheses

0.3x-1.2

Back to the equation:

-(0.3x-1.2)



We add all the numbers together, and all the variables

2.4x-(0.3x-1.2)-11.7=0

We get rid of parentheses

2.4x-0.3x+1.2-11.7=0

We add all the numbers together, and all the variables

2.1x-10.5=0

We move all terms containing x to the left, all other terms to the right

2.1x=10.5

x=10.5/2.1

x=5

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