0-25=(8x+5)(8x-5)

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Solution for 0-25=(8x+5)(8x-5) equation: 



0-25=(8x+5)(8x-5)

We move all terms to the left:

0-25-((8x+5)(8x-5))=0

We add all the numbers together, and all the variables

-((8x+5)(8x-5))-25=0

We use the square of the difference formula

64x^2+25-25=0

We add all the numbers together, and all the variables

64x^2=0

a = 64; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·64·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{128}=0$

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