0.002(1-x)+0.01(x-3)=1

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Solution for 0.002(1-x)+0.01(x-3)=1 equation: 



0.002(1-x)+0.01(x-3)=1

We move all terms to the left:

0.002(1-x)+0.01(x-3)-(1)=0

We add all the numbers together, and all the variables

0.002(-1x+1)+0.01(x-3)-1=0

We multiply parentheses

-0.002x+0.01x+0.002-0.03-1=0

We add all the numbers together, and all the variables

0.008x-1.028=0

We move all terms containing x to the left, all other terms to the right

0.008x=1.028

x=1.028/0.008

x=128+0.004/0.008

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