0.002(3-k)+0.01(k-1)=1

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Solution for 0.002(3-k)+0.01(k-1)=1 equation: 



0.002(3-k)+0.01(k-1)=1

We move all terms to the left:

0.002(3-k)+0.01(k-1)-(1)=0

We add all the numbers together, and all the variables

0.002(-1k+3)+0.01(k-1)-1=0

We multiply parentheses

-0.002k+0.01k+0.006-0.01-1=0

We add all the numbers together, and all the variables

0.008k-1.004=0

We move all terms containing k to the left, all other terms to the right

0.008k=1.004

k=1.004/0.008

k=125+0.004/0.008

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