0.002(4-k)+0.04(k-3)=1

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Solution for 0.002(4-k)+0.04(k-3)=1 equation: 



0.002(4-k)+0.04(k-3)=1

We move all terms to the left:

0.002(4-k)+0.04(k-3)-(1)=0

We add all the numbers together, and all the variables

0.002(-1k+4)+0.04(k-3)-1=0

We multiply parentheses

-0.002k+0.04k+0.008-0.12-1=0

We add all the numbers together, and all the variables

0.038k-1.112=0

We move all terms containing k to the left, all other terms to the right

0.038k=1.112

k=1.112/0.038

k=29+0.01/0.038

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