0.002(6-k)+0.07(k-3)=1

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Solution for 0.002(6-k)+0.07(k-3)=1 equation: 



0.002(6-k)+0.07(k-3)=1

We move all terms to the left:

0.002(6-k)+0.07(k-3)-(1)=0

We add all the numbers together, and all the variables

0.002(-1k+6)+0.07(k-3)-1=0

We multiply parentheses

-0.002k+0.07k+0.012-0.21-1=0

We add all the numbers together, and all the variables

0.068k-1.198=0

We move all terms containing k to the left, all other terms to the right

0.068k=1.198

k=1.198/0.068

k=17+0.042/0.068

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