0.02(2t-9)=0.04(t+1)-0.22

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Solution for 0.02(2t-9)=0.04(t+1)-0.22 equation:


Simplifying
0.02(2t + -9) = 0.04(t + 1) + -0.22

Reorder the terms:
0.02(-9 + 2t) = 0.04(t + 1) + -0.22
(-9 * 0.02 + 2t * 0.02) = 0.04(t + 1) + -0.22
(-0.18 + 0.04t) = 0.04(t + 1) + -0.22

Reorder the terms:
-0.18 + 0.04t = 0.04(1 + t) + -0.22
-0.18 + 0.04t = (1 * 0.04 + t * 0.04) + -0.22
-0.18 + 0.04t = (0.04 + 0.04t) + -0.22

Reorder the terms:
-0.18 + 0.04t = 0.04 + -0.22 + 0.04t

Combine like terms: 0.04 + -0.22 = -0.18
-0.18 + 0.04t = -0.18 + 0.04t

Add '0.18' to each side of the equation.
-0.18 + 0.18 + 0.04t = -0.18 + 0.18 + 0.04t

Combine like terms: -0.18 + 0.18 = 0.00
0.00 + 0.04t = -0.18 + 0.18 + 0.04t
0.04t = -0.18 + 0.18 + 0.04t

Combine like terms: -0.18 + 0.18 = 0.00
0.04t = 0.00 + 0.04t
0.04t = 0.04t

Add '-0.04t' to each side of the equation.
0.04t + -0.04t = 0.04t + -0.04t

Combine like terms: 0.04t + -0.04t = 0.00
0.00 = 0.04t + -0.04t

Combine like terms: 0.04t + -0.04t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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