0.02(6t-5)=0.12(t-5)+0.7

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Solution for 0.02(6t-5)=0.12(t-5)+0.7 equation: 



0.02(6t-5)=0.12(t-5)+0.7

We move all terms to the left:

0.02(6t-5)-(0.12(t-5)+0.7)=0

We multiply parentheses

0.12t-(0.12(t-5)+0.7)-0.1=0



We calculate terms in parentheses: -(0.12(t-5)+0.7), so:

0.12(t-5)+0.7

We multiply parentheses

0.12t-0.6+0.7

We add all the numbers together, and all the variables

0.12t+0.1

Back to the equation:

-(0.12t+0.1)



We get rid of parentheses

0.12t-0.12t-0.1-0.1=0

We add all the numbers together, and all the variables

-0.2!=0

There is no solution for this equation

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