0.02(6t-5)=0.12(t-5)+0.7

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Solution for 0.02(6t-5)=0.12(t-5)+0.7 equation:



0.02(6t-5)=0.12(t-5)+0.7
We move all terms to the left:
0.02(6t-5)-(0.12(t-5)+0.7)=0
We multiply parentheses
0.12t-(0.12(t-5)+0.7)-0.1=0
We calculate terms in parentheses: -(0.12(t-5)+0.7), so:
0.12(t-5)+0.7
We multiply parentheses
0.12t-0.6+0.7
We add all the numbers together, and all the variables
0.12t+0.1
Back to the equation:
-(0.12t+0.1)
We get rid of parentheses
0.12t-0.12t-0.1-0.1=0
We add all the numbers together, and all the variables
-0.2!=0
There is no solution for this equation

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