0.02-0.01(x+1)=-0.01(3-x)

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Solution for 0.02-0.01(x+1)=-0.01(3-x) equation: 



0.02-0.01(x+1)=-0.01(3-x)

We move all terms to the left:

0.02-0.01(x+1)-(-0.01(3-x))=0

We add all the numbers together, and all the variables

-0.01(x+1)-(-0.01(-1x+3))+0.02=0

We multiply parentheses

-0.01x-(-0.01(-1x+3))-0.01+0.02=0



We calculate terms in parentheses: -(-0.01(-1x+3)), so:

-0.01(-1x+3)

We multiply parentheses

0.01x-0.03

Back to the equation:

-(0.01x-0.03)



We add all the numbers together, and all the variables

-0.01x-(0.01x-0.03)+0.01=0

We get rid of parentheses

-0.01x-0.01x+0.03+0.01=0

We add all the numbers together, and all the variables

-0.02x+0.04=0

We move all terms containing x to the left, all other terms to the right

-0.02x=-0.04

x=-0.04/-0.02

x=+2

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