0.02x+0.03(11000-x)=290

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Solution for 0.02x+0.03(11000-x)=290 equation: 



0.02x+0.03(11000-x)=290

We move all terms to the left:

0.02x+0.03(11000-x)-(290)=0

We add all the numbers together, and all the variables

0.02x+0.03(-1x+11000)-290=0

We multiply parentheses

0.02x-0.03x+330-290=0

We add all the numbers together, and all the variables

-0.01x+40=0

We move all terms containing x to the left, all other terms to the right

-0.01x=-40

x=-40/-0.01

x=+4000

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