0.03(4t+3)=0.12(t-3)+0.45

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Solution for 0.03(4t+3)=0.12(t-3)+0.45 equation: 



0.03(4t+3)=0.12(t-3)+0.45

We move all terms to the left:

0.03(4t+3)-(0.12(t-3)+0.45)=0

We multiply parentheses

0.12t-(0.12(t-3)+0.45)+0.09=0



We calculate terms in parentheses: -(0.12(t-3)+0.45), so:

0.12(t-3)+0.45

We multiply parentheses

0.12t-0.36+0.45

We add all the numbers together, and all the variables

0.12t+0.09

Back to the equation:

-(0.12t+0.09)



We get rid of parentheses

0.12t-0.12t-0.09+0.09=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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