0.03(4t+7)=0.12(t+2)-0.03

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Solution for 0.03(4t+7)=0.12(t+2)-0.03 equation: 


Simplifying
0.03(4t + 7) = 0.12(t + 2) + -0.03

Reorder the terms:
0.03(7 + 4t) = 0.12(t + 2) + -0.03
(7 * 0.03 + 4t * 0.03) = 0.12(t + 2) + -0.03
(0.21 + 0.12t) = 0.12(t + 2) + -0.03

Reorder the terms:
0.21 + 0.12t = 0.12(2 + t) + -0.03
0.21 + 0.12t = (2 * 0.12 + t * 0.12) + -0.03
0.21 + 0.12t = (0.24 + 0.12t) + -0.03

Reorder the terms:
0.21 + 0.12t = 0.24 + -0.03 + 0.12t

Combine like terms: 0.24 + -0.03 = 0.21
0.21 + 0.12t = 0.21 + 0.12t

Add '-0.21' to each side of the equation.
0.21 + -0.21 + 0.12t = 0.21 + -0.21 + 0.12t

Combine like terms: 0.21 + -0.21 = 0.00
0.00 + 0.12t = 0.21 + -0.21 + 0.12t
0.12t = 0.21 + -0.21 + 0.12t

Combine like terms: 0.21 + -0.21 = 0.00
0.12t = 0.00 + 0.12t
0.12t = 0.12t

Add '-0.12t' to each side of the equation.
0.12t + -0.12t = 0.12t + -0.12t

Combine like terms: 0.12t + -0.12t = 0.00
0.00 = 0.12t + -0.12t

Combine like terms: 0.12t + -0.12t = 0.00
0.00 = 0.00

Solving
0.00 = 0.00

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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