0.03(5t-9)=0.15(t+2)-0.57

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Solution for 0.03(5t-9)=0.15(t+2)-0.57 equation: 



0.03(5t-9)=0.15(t+2)-0.57

We move all terms to the left:

0.03(5t-9)-(0.15(t+2)-0.57)=0

We multiply parentheses

0.15t-(0.15(t+2)-0.57)-0.27=0



We calculate terms in parentheses: -(0.15(t+2)-0.57), so:

0.15(t+2)-0.57

We multiply parentheses

0.15t+0.3-0.57

We add all the numbers together, and all the variables

0.15t-0.27

Back to the equation:

-(0.15t-0.27)



We get rid of parentheses

0.15t-0.15t+0.27-0.27=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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