0.0333x2+2x-45=0

Solution for 0.0333x2+2x-45=0 equation:

0.0333x^2+2x-45=0

a = 0.0333; b = 2; c = -45;
Δ = b2-4ac
Δ = 22-4·0.0333·(-45)
Δ = 9.994
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{9.994}}{2*0.0333}=\frac{-2-\sqrt{9.994}}{0.0666}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{9.994}}{2*0.0333}=\frac{-2+\sqrt{9.994}}{0.0666}
$