0.04(y-3)+0.12y=0.06y-0.03(20)

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Solution for 0.04(y-3)+0.12y=0.06y-0.03(20) equation: 



0.04(y-3)+0.12y=0.06y-0.03(20)

We move all terms to the left:

0.04(y-3)+0.12y-(0.06y-0.03(20))=0

We add all the numbers together, and all the variables

0.04(y-3)+0.12y-(0.06y-0.032)=0

We add all the numbers together, and all the variables

0.12y+0.04(y-3)-(0.06y-0.032)=0

We multiply parentheses

0.12y+0.04y-(0.06y-0.032)-0.12=0

We get rid of parentheses

0.12y+0.04y-0.06y+0.032-0.12=0

We add all the numbers together, and all the variables

0.1y-0.088=0

We move all terms containing y to the left, all other terms to the right

0.1y=0.088

y=0.088/0.1

y=0.088/0.1

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