0.04(y-4)+0.06y=-0.12y-0.01(30)

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Solution for 0.04(y-4)+0.06y=-0.12y-0.01(30) equation: 



0.04(y-4)+0.06y=-0.12y-0.01(30)

We move all terms to the left:

0.04(y-4)+0.06y-(-0.12y-0.01(30))=0

We add all the numbers together, and all the variables

0.04(y-4)+0.06y-(-0.12y-0.013)=0

We add all the numbers together, and all the variables

0.06y+0.04(y-4)-(-0.12y-0.013)=0

We multiply parentheses

0.06y+0.04y-(-0.12y-0.013)-0.16=0

We get rid of parentheses

0.06y+0.04y+0.12y+0.013-0.16=0

We add all the numbers together, and all the variables

0.22y-0.147=0

We move all terms containing y to the left, all other terms to the right

0.22y=0.147

y=0.147/0.22

y=0.147/0.22

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