0.04x(6x-1)=0.2x+5

Solution for 0.04x(6x-1)=0.2x+5 equation:

0.04x(6x-1)=0.2x+5

We move all terms to the left:

0.04x(6x-1)-(0.2x+5)=0

We multiply parentheses

0x^2+0x-(0.2x+5)=0

We get rid of parentheses

0x^2+0x-0.2x-5=0

We add all the numbers together, and all the variables

x^2+0.8x-5=0

a = 1; b = 0.8; c = -5;
Δ = b2-4ac
Δ = 0.82-4·1·(-5)
Δ = 20.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.8)-\sqrt{20.64}}{2*1}=\frac{-0.8-\sqrt{20.64}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.8)+\sqrt{20.64}}{2*1}=\frac{-0.8+\sqrt{20.64}}{2}
$