0.04x+0.05(2x+1200)=141

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Solution for 0.04x+0.05(2x+1200)=141 equation: 



0.04x+0.05(2x+1200)=141

We move all terms to the left:

0.04x+0.05(2x+1200)-(141)=0

We multiply parentheses

0.04x+0.1x+60-141=0

We add all the numbers together, and all the variables

0.14x-81=0

We move all terms containing x to the left, all other terms to the right

0.14x=81

x=81/0.14

x=578+0.08/0.14

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