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0.04x+0.10x(400-x)=0.44x
We move all terms to the left:
0.04x+0.10x(400-x)-(0.44x)=0
We add all the numbers together, and all the variables
0.04x+0.10x(-1x+400)-(+0.44x)=0
We multiply parentheses
0x^2+0.04x+0x-(+0.44x)=0
We get rid of parentheses
0x^2+0.04x+0x-0.44x=0
We add all the numbers together, and all the variables
x^2+0.6x=0
a = 1; b = 0.6; c = 0;
Δ = b2-4ac
Δ = 0.62-4·1·0
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{0.36}}{2*1}=\frac{-0.6-\sqrt{0.36}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{0.36}}{2*1}=\frac{-0.6+\sqrt{0.36}}{2} $
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