0.06-0.02(x+2)=-0.01(1-x)

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Solution for 0.06-0.02(x+2)=-0.01(1-x) equation: 



0.06-0.02(x+2)=-0.01(1-x)

We move all terms to the left:

0.06-0.02(x+2)-(-0.01(1-x))=0

We add all the numbers together, and all the variables

-0.02(x+2)-(-0.01(-1x+1))+0.06=0

We multiply parentheses

-0.02x-(-0.01(-1x+1))-0.04+0.06=0



We calculate terms in parentheses: -(-0.01(-1x+1)), so:

-0.01(-1x+1)

We multiply parentheses

0.01x-0.01

Back to the equation:

-(0.01x-0.01)



We add all the numbers together, and all the variables

-0.02x-(0.01x-0.01)+0.02=0

We get rid of parentheses

-0.02x-0.01x+0.01+0.02=0

We add all the numbers together, and all the variables

-0.03x+0.03=0

We move all terms containing x to the left, all other terms to the right

-0.03x=-0.03

x=-0.03/-0.03

x=1

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