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0.1(4x+1)(2x+2)=0
We multiply parentheses ..
0.1(+8x^2+8x+2x+2)=0
We multiply parentheses
0.8x^2+0.8x+0.2x+0.2=0
We add all the numbers together, and all the variables
0.8x^2+x+0.2=0
a = 0.8; b = 1; c = +0.2;
Δ = b2-4ac
Δ = 12-4·0.8·0.2
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{0.36}}{2*0.8}=\frac{-1-\sqrt{0.36}}{1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{0.36}}{2*0.8}=\frac{-1+\sqrt{0.36}}{1.6} $
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