0.1(n+2)=0.4(3n-1)

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Solution for 0.1(n+2)=0.4(3n-1) equation: 



0.1(n+2)=0.4(3n-1)

We move all terms to the left:

0.1(n+2)-(0.4(3n-1))=0

We multiply parentheses

0.1n-(0.4(3n-1))+0.2=0



We calculate terms in parentheses: -(0.4(3n-1)), so:

0.4(3n-1)

We multiply parentheses

1.2n-0.4

Back to the equation:

-(1.2n-0.4)



We get rid of parentheses

0.1n-1.2n+0.4+0.2=0

We add all the numbers together, and all the variables

-1.1n+0.6=0

We move all terms containing n to the left, all other terms to the right

-1.1n=-0.6

n=-0.6/-1.1

n=0.6/1.1

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