0.10x+(0.15)(20)=0.12(20+x)

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Solution for 0.10x+(0.15)(20)=0.12(20+x) equation: 



0.10x+(0.15)(20)=0.12(20+x)

We move all terms to the left:

0.10x+(0.15)(20)-(0.12(20+x))=0

We add all the numbers together, and all the variables

0.10x-(0.12(x+20))+(0.15)20=0

We add all the numbers together, and all the variables

0.10x-(0.12(x+20))+3=0



We calculate terms in parentheses: -(0.12(x+20)), so:

0.12(x+20)

We multiply parentheses

0.12x+2.4

Back to the equation:

-(0.12x+2.4)



We get rid of parentheses

0.10x-0.12x-2.4+3=0

We add all the numbers together, and all the variables

-0.02x+0.6=0

We move all terms containing x to the left, all other terms to the right

-0.02x=-0.6

x=-0.6/-0.02

x=+30

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