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0.10x+0.12(x2)=2890
We move all terms to the left:
0.10x+0.12(x2)-(2890)=0
We add all the numbers together, and all the variables
0.12x^2+0.10x-2890=0
a = 0.12; b = 0.10; c = -2890;
Δ = b2-4ac
Δ = 0.102-4·0.12·(-2890)
Δ = 1387.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.10)-\sqrt{1387.21}}{2*0.12}=\frac{-0.1-\sqrt{1387.21}}{0.24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.10)+\sqrt{1387.21}}{2*0.12}=\frac{-0.1+\sqrt{1387.21}}{0.24} $
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