0.11(2n-6)-n=0.22(4-4n)

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Solution for 0.11(2n-6)-n=0.22(4-4n) equation: 



0.11(2n-6)-n=0.22(4-4n)

We move all terms to the left:

0.11(2n-6)-n-(0.22(4-4n))=0

We add all the numbers together, and all the variables

0.11(2n-6)-n-(0.22(-4n+4))=0

We add all the numbers together, and all the variables

-1n+0.11(2n-6)-(0.22(-4n+4))=0

We multiply parentheses

-1n+0.22n-(0.22(-4n+4))-0.66=0



We calculate terms in parentheses: -(0.22(-4n+4)), so:

0.22(-4n+4)

We multiply parentheses

-0.88n+0.88

Back to the equation:

-(-0.88n+0.88)



We add all the numbers together, and all the variables

-0.78n-(-0.88n+0.88)-0.66=0

We get rid of parentheses

-0.78n+0.88n-0.88-0.66=0

We add all the numbers together, and all the variables

0.1n-1.54=0

We move all terms containing n to the left, all other terms to the right

0.1n=1.54

n=1.54/0.1

n=15+0.04/0.1

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