0.11(y-4)+0.11y=0.002y-0.40

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Solution for 0.11(y-4)+0.11y=0.002y-0.40 equation: 



0.11(y-4)+0.11y=0.002y-0.40

We move all terms to the left:

0.11(y-4)+0.11y-(0.002y-0.40)=0

We add all the numbers together, and all the variables

0.11(y-4)+0.11y-(0.002y-0.4)=0

We add all the numbers together, and all the variables

0.11y+0.11(y-4)-(0.002y-0.4)=0

We multiply parentheses

0.11y+0.11y-(0.002y-0.4)-0.44=0

We get rid of parentheses

0.11y+0.11y-0.002y+0.4-0.44=0

We add all the numbers together, and all the variables

0.218y-0.04=0

We move all terms containing y to the left, all other terms to the right

0.218y=0.04

y=0.04/0.218

y=0.04/0.218

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