0.11x+0.2(x-2)=0.01(5x-3)fraction

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Solution for 0.11x+0.2(x-2)=0.01(5x-3)fraction equation:


Simplifying
0.11x + 0.2(x + -2) = 0.01(5x + -3) * fraction

Reorder the terms:
0.11x + 0.2(-2 + x) = 0.01(5x + -3) * fraction
0.11x + (-2 * 0.2 + x * 0.2) = 0.01(5x + -3) * fraction
0.11x + (-0.4 + 0.2x) = 0.01(5x + -3) * fraction

Reorder the terms:
-0.4 + 0.11x + 0.2x = 0.01(5x + -3) * fraction

Combine like terms: 0.11x + 0.2x = 0.31x
-0.4 + 0.31x = 0.01(5x + -3) * fraction

Reorder the terms:
-0.4 + 0.31x = 0.01(-3 + 5x) * fraction

Reorder the terms for easier multiplication:
-0.4 + 0.31x = 0.01acfinort(-3 + 5x)
-0.4 + 0.31x = (-3 * 0.01acfinort + 5x * 0.01acfinort)
-0.4 + 0.31x = (-0.03acfinort + 0.05acfinortx)

Solving
-0.4 + 0.31x = -0.03acfinort + 0.05acfinortx

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-0.05acfinortx' to each side of the equation.
-0.4 + -0.05acfinortx + 0.31x = -0.03acfinort + 0.05acfinortx + -0.05acfinortx

Combine like terms: 0.05acfinortx + -0.05acfinortx = 0.00
-0.4 + -0.05acfinortx + 0.31x = -0.03acfinort + 0.00
-0.4 + -0.05acfinortx + 0.31x = -0.03acfinort

Add '0.4' to each side of the equation.
-0.4 + -0.05acfinortx + 0.4 + 0.31x = 0.4 + -0.03acfinort

Reorder the terms:
-0.4 + 0.4 + -0.05acfinortx + 0.31x = 0.4 + -0.03acfinort

Combine like terms: -0.4 + 0.4 = 0.0
0.0 + -0.05acfinortx + 0.31x = 0.4 + -0.03acfinort
-0.05acfinortx + 0.31x = 0.4 + -0.03acfinort

Reorder the terms:
-0.4 + 0.03acfinort + -0.05acfinortx + 0.31x = 0.4 + -0.03acfinort + -0.4 + 0.03acfinort

Reorder the terms:
-0.4 + 0.03acfinort + -0.05acfinortx + 0.31x = 0.4 + -0.4 + -0.03acfinort + 0.03acfinort

Combine like terms: 0.4 + -0.4 = 0.0
-0.4 + 0.03acfinort + -0.05acfinortx + 0.31x = 0.0 + -0.03acfinort + 0.03acfinort
-0.4 + 0.03acfinort + -0.05acfinortx + 0.31x = -0.03acfinort + 0.03acfinort

Combine like terms: -0.03acfinort + 0.03acfinort = 0.00
-0.4 + 0.03acfinort + -0.05acfinortx + 0.31x = 0.00

The solution to this equation could not be determined.

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