0.11x+0.7(x-3)=0.01(4x-2)

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Solution for 0.11x+0.7(x-3)=0.01(4x-2) equation: 



0.11x+0.7(x-3)=0.01(4x-2)

We move all terms to the left:

0.11x+0.7(x-3)-(0.01(4x-2))=0

We multiply parentheses

0.11x+0.7x-(0.01(4x-2))-2.1=0



We calculate terms in parentheses: -(0.01(4x-2)), so:

0.01(4x-2)

We multiply parentheses

0.04x-0.02

Back to the equation:

-(0.04x-0.02)



We add all the numbers together, and all the variables

0.81x-(0.04x-0.02)-2.1=0

We get rid of parentheses

0.81x-0.04x+0.02-2.1=0

We add all the numbers together, and all the variables

0.77x-2.08=0

We move all terms containing x to the left, all other terms to the right

0.77x=2.08

x=2.08/0.77

x=2+0.54/0.77

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