0.11x+0.8(x-2)=0.01(4x-3)

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Solution for 0.11x+0.8(x-2)=0.01(4x-3) equation: 



0.11x+0.8(x-2)=0.01(4x-3)

We move all terms to the left:

0.11x+0.8(x-2)-(0.01(4x-3))=0

We multiply parentheses

0.11x+0.8x-(0.01(4x-3))-1.6=0



We calculate terms in parentheses: -(0.01(4x-3)), so:

0.01(4x-3)

We multiply parentheses

0.04x-0.03

Back to the equation:

-(0.04x-0.03)



We add all the numbers together, and all the variables

0.91x-(0.04x-0.03)-1.6=0

We get rid of parentheses

0.91x-0.04x+0.03-1.6=0

We add all the numbers together, and all the variables

0.87x-1.57=0

We move all terms containing x to the left, all other terms to the right

0.87x=1.57

x=1.57/0.87

x=1+0.7/0.87

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