0.12(12)+0.03=0.06(6+x)

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Solution for 0.12(12)+0.03=0.06(6+x) equation:



0.12(12)+0.03=0.06(6+x)
We move all terms to the left:
0.12(12)+0.03-(0.06(6+x))=0
We add all the numbers together, and all the variables
-(0.06(x+6))+0.03+0.1212=0
We add all the numbers together, and all the variables
-(0.06(x+6))+0.1512=0
We calculate terms in parentheses: -(0.06(x+6)), so:
0.06(x+6)
We multiply parentheses
0.06x+0.36
Back to the equation:
-(0.06x+0.36)
We get rid of parentheses
-0.06x-0.36+0.1512=0
We add all the numbers together, and all the variables
-0.06x-0.2088=0
We move all terms containing x to the left, all other terms to the right
-0.06x=0.2088
x=0.2088/-0.06
x=-3+0.0288/0.06

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