0.12(12)+0.3x=0.06(12+x)

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Solution for 0.12(12)+0.3x=0.06(12+x) equation: 



0.12(12)+0.3x=0.06(12+x)

We move all terms to the left:

0.12(12)+0.3x-(0.06(12+x))=0

We add all the numbers together, and all the variables

0.3x-(0.06(x+12))+0.1212=0



We calculate terms in parentheses: -(0.06(x+12)), so:

0.06(x+12)

We multiply parentheses

0.06x+0.72

Back to the equation:

-(0.06x+0.72)



We get rid of parentheses

0.3x-0.06x-0.72+0.1212=0

We add all the numbers together, and all the variables

0.24x-0.5988=0

We move all terms containing x to the left, all other terms to the right

0.24x=0.5988

x=0.5988/0.24

x=2+0.1188/0.24

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