0.12(2y-2)=0.15(y+4)

Solution for 0.12(2y-2)=0.15(y+4) equation:

0.12(2y-2)=0.15(y+4)

We move all terms to the left:

0.12(2y-2)-(0.15(y+4))=0

We multiply parentheses

0.24y-(0.15(y+4))-0.24=0


We calculate terms in parentheses: -(0.15(y+4)), so:

0.15(y+4)

We multiply parentheses

0.15y+0.6

Back to the equation:

-(0.15y+0.6)


We get rid of parentheses

0.24y-0.15y-0.6-0.24=0

We add all the numbers together, and all the variables

0.09y-0.84=0

We move all terms containing y to the left, all other terms to the right

0.09y=0.84

y=0.84/0.09

y=9+0.03/0.09